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Solve 2x^(2)=162.
The solutions are x= ◻ and x= ◻.

Solve 2x2=162 2 x^{2}=162 .\newlineThe solutions are x= x= \square and x= x= \square .

Full solution

Q. Solve 2x2=162 2 x^{2}=162 .\newlineThe solutions are x= x= \square and x= x= \square .
  1. Divide by 22: Given the equation 2x2=12x^{2} = 1, we want to find the values of xx that satisfy this equation.\newlineFirst, we divide both sides of the equation by 22 to isolate x2x^{2}.\newlinex2=12x^{2} = \frac{1}{2}
  2. Take square root: Next, we take the square root of both sides of the equation to solve for xx.x2=±12\sqrt{x^{2}} = \pm\sqrt{\frac{1}{2}} This gives us x=±12x = \pm\sqrt{\frac{1}{2}}.
  3. Simplify square root: To simplify 12\sqrt{\frac{1}{2}}, we can rewrite it as 1/2\sqrt{1}/\sqrt{2}, which simplifies to 12\frac{1}{\sqrt{2}}. Since it is often preferred to rationalize the denominator, we multiply the numerator and denominator by 2\sqrt{2} to get 22\frac{\sqrt{2}}{2}. So, x=±22x = \pm\frac{\sqrt{2}}{2}.

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