Problem: We are asked to find the limit of the function sin(x) as x approaches 6π. The sine function is continuous everywhere, so we can find this limit by direct substitution.
Step 1: Substitute x with 6π in the sine function: sin(6π).
Step 2: Calculate the value of sin(6π). The sine of 6π is a well-known value, which is 21.
Step 3: Therefore, the limit of sin(x) as x approaches 6π is 21.
More problems from Domain and range of square root functions: equations