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lim_(x rarr-(pi)/(2))tan(x)=?
Choose 1 answer:
(A) -1
(B) 
-(1)/(2)
(C) 0
(D) The limit doesn't exist.

limxπ2tan(x)=? \lim _{x \rightarrow-\frac{\pi}{2}} \tan (x)=? \newlineChoose 11 answer:\newline(A) 1-1\newline(B) 12 -\frac{1}{2} \newline(C) 00\newline(D) The limit doesn't exist.

Full solution

Q. limxπ2tan(x)=? \lim _{x \rightarrow-\frac{\pi}{2}} \tan (x)=? \newlineChoose 11 answer:\newline(A) 1-1\newline(B) 12 -\frac{1}{2} \newline(C) 00\newline(D) The limit doesn't exist.
  1. Step 11: Determine the function and point of interest: We need to find the limit of the function tan(x)\tan(x) as xx approaches π2-\frac{\pi}{2}. The tangent function has a period of π\pi, and it is known to have vertical asymptotes (where the function is undefined) at odd multiples of π2\frac{\pi}{2}. Since π2-\frac{\pi}{2} is one such point, we expect the limit to not exist because the tangent function approaches negative infinity from the right and positive infinity from the left of π2-\frac{\pi}{2}.
  2. Step 22: Analyze the behavior of sine and cosine functions: To confirm our expectation, we can consider the behavior of the sine and cosine functions separately, as tan(x)=sin(x)cos(x)\tan(x) = \frac{\sin(x)}{\cos(x)}. As xx approaches π2-\frac{\pi}{2}, sin(x)\sin(x) approaches 1-1 and cos(x)\cos(x) approaches 00. The cosine function approaches 00 through positive values from the right of π2-\frac{\pi}{2} and through negative values from the left of π2-\frac{\pi}{2}.
  3. Step 33: Observe the sign change of cosine function: Since the cosine function changes sign around (π)/(2)-(\pi)/(2), the tangent function will have opposite behaviors on either side of (π)/(2)-(\pi)/(2). From the right, tan(x)\tan(x) will approach negative infinity, and from the left, it will approach positive infinity. This confirms that the limit does not exist because the left-hand limit and the right-hand limit are not equal.
  4. Step 44: Determine the behavior of tangent function: Therefore, the correct answer is (D) The limit doesn't exist, because the function tan(x)\tan(x) does not approach a single finite value as xx approaches π2-\frac{\pi}{2}.

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