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lim_(x rarr oo)(-4x^(2)+3x+6)/(2x^(2)+1x-8)=_____

limx4x2+3x+62x2+1x8=_____ \lim _{x \rightarrow \infty} \frac{-4 x^{2}+3 x+6}{2 x^{2}+1 x-8}=\_\_\_\_\_

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Q. limx4x2+3x+62x2+1x8=_____ \lim _{x \rightarrow \infty} \frac{-4 x^{2}+3 x+6}{2 x^{2}+1 x-8}=\_\_\_\_\_
  1. Analyze Behavior of Terms: To find the limit of the function as xx approaches infinity, we need to analyze the behavior of the numerator and the denominator. Since both the numerator and the denominator are polynomials of the same degree (degree 22), we can compare the leading coefficients of the x2x^2 terms.
  2. Compare Leading Coefficients: The leading term in the numerator is 4x2-4x^2 and the leading term in the denominator is 2x22x^2. To find the limit as xx approaches infinity, we can divide the coefficients of the leading terms.
  3. Divide Coefficients: Dividing the coefficients of the leading terms gives us 4/2-4/2, which simplifies to 2-2.
  4. Find Limit: Therefore, the limit of the function as xx approaches \infty is 2-2.

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