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Lily measured a line to be 2.7 inches long. If the actual length of the line is 2.6 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?
Answer: 
%

Lily measured a line to be 22.77 inches long. If the actual length of the line is 22.66 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?\newlineAnswer: ________% \%

Full solution

Q. Lily measured a line to be 22.77 inches long. If the actual length of the line is 22.66 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?\newlineAnswer: ________% \%
  1. Understand formula: Understand the percent error formula.\newlinePercent error is calculated using the formula: \newlinePercent Error = (Measured ValueActual Value/Actual Value)×100%(|\text{Measured Value} - \text{Actual Value}| / \text{Actual Value}) \times 100\%\newlineHere, the measured value is 2.72.7 inches, and the actual value is 2.62.6 inches.
  2. Plug in values: Plug in the values into the percent error formula.\newlinePercent Error = (2.72.6/2.6)×100%(|2.7 - 2.6| / 2.6) \times 100\%
  3. Calculate absolute difference: Calculate the absolute difference between the measured value and the actual value.\newline2.72.6=0.1|2.7 - 2.6| = 0.1 inches
  4. Divide by actual value: Divide the absolute difference by the actual value.\newline0.12.6=0.03846153846\frac{0.1}{2.6} = 0.03846153846 (This is the decimal form of the percent error.)
  5. Convert to percentage: Convert the decimal to a percentage. 0.03846153846×100%=3.846153846%0.03846153846 \times 100\% = 3.846153846\%
  6. Round to nearest tenth: Round the percent error to the nearest tenth of a percent. 3.846153846%3.846153846\% rounds to 3.8%3.8\%

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