Let h(x)=(x^(2)-49)/(x+7) when x!=-7. h is continuous for all real numbers. Find h(-7). Choose 1 answer: (A) -7 (B) 14 (c) 7 (D) -14

Simplify function h(x): First, we need to simplify the function h(x) to see if we can evaluate it at x = -7 without causing a division by zero. h(x) = (x^2 - 49) / (x + 7) We notice that x^2 - 49 is a difference of squares and can be factored as (x + 7)(x - 7). h(x) = [(x + 7)(x - 7)] / (x + 7)Cancel out common factor: Next, we can cancel out the common factor (x + 7) in the numerator and the denominator, as long as x is not equal to -7, to avoid division by zero. h(x) = (x - 7) for x ≠ -7Evaluate h(x) at x = -7: Now that we have simplified the function, we can evaluate h(x) at x = -7. h(-7) = (-7 - 7) h(-7) = -14

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Let
h(x)=(x^(2)-49)/(x+7) when
x!=-7.

h is continuous for all real numbers.
Find
h(-7).
Choose 1 answer:
(A) -7
(B) 14
(c) 7
(D) -14

Let $h(x)=\frac{x^{2}-49}{x+7}$ when $x \neq-7$ . $\newline$ $h$ is continuous for all real numbers. $\newline$ Find $h(-7)$ . $\newline$ Choose $1$ answer: $\newline$ (A) $-7$ $\newline$ (B) $14$ $\newline$ (C) $7$ $\newline$ (D) $-14$

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Math Problems

Algebra 1

Domain and range of quadratic functions: equations

Full solution

Q. Let

h(x)=\frac{x^{2}-49}{x+7}

when

x \neq-7

\newline

h

is continuous for all real numbers.

\newline

Find

h(-7)

\newline

Choose

1

answer:

\newline

(A)

-7

\newline

(B)

14

\newline

(C)

7

\newline

(D)

-14

Simplify function $h(x)$ : First, we need to simplify the function $h(x)$ to see if we can evaluate it at $x = -7$ without causing a division by zero. $\newline$ $h(x) = \frac{x^2 - 49}{x + 7}$ $\newline$ We notice that $x^2 - 49$ is a difference of squares and can be factored as $(x + 7)(x - 7)$ . $\newline$ $h(x) = \frac{[(x + 7)(x - 7)]}{(x + 7)}$
Cancel out common factor: Next, we can cancel out the common factor $(x + 7)$ in the numerator and the denominator, as long as $x$ is not equal to $-7$ , to avoid division by zero. $h(x) = (x - 7)$ for $x \neq -7$
Evaluate $h(x)$ at $x = -7$ : Now that we have simplified the function, we can evaluate $h(x)$ at $x = -7$ .
$h(-7) = (-7 - 7)$
$h(-7) = -14$