Q. Let g(x)=x−4x2−x−12 when x=4.g is continuous for all real numbers.Find g(4).Choose 1 answer:(A) −4(B) −3(C) 4(D) 7
Simplify g(x): First, we need to simplify the function g(x) to see if we can define it at x=4, since the original function has a discontinuity at x=4. g(x)=x−4x2−x−12 Factor the numerator to find common factors with the denominator. x2−x−12 can be factored into (x−4)(x+3). So, g(x)=x−4(x−4)(x+3)
Cancel common factor: Next, we cancel out the common factor (x−4) from the numerator and the denominator, as long as x=4. g(x)=(x+3) for x=4 Now, we can define g(4) by substituting x with 4. g(4)=4+3
Define g(4): Calculate the value of g(4).g(4)=4+3=7
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