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Let 
g(x)=(x^(2)-x-12)/(x-4) when 
x!=4.

g is continuous for all real numbers.
Find 
g(4).
Choose 1 answer:
(A) -4
(B) -3
(c) 4
(D) 7

Let g(x)=x2x12x4 g(x)=\frac{x^{2}-x-12}{x-4} when x4 x \neq 4 .\newlineg g is continuous for all real numbers.\newlineFind g(4) g(4) .\newlineChoose 11 answer:\newline(A) 4-4\newline(B) 3-3\newline(C) 44\newline(D) 77

Full solution

Q. Let g(x)=x2x12x4 g(x)=\frac{x^{2}-x-12}{x-4} when x4 x \neq 4 .\newlineg g is continuous for all real numbers.\newlineFind g(4) g(4) .\newlineChoose 11 answer:\newline(A) 4-4\newline(B) 3-3\newline(C) 44\newline(D) 77
  1. Simplify g(x)g(x): First, we need to simplify the function g(x)g(x) to see if we can define it at x=4x = 4, since the original function has a discontinuity at x=4x = 4.
    g(x)=x2x12x4g(x) = \frac{x^2 - x - 12}{x - 4}
    Factor the numerator to find common factors with the denominator.
    x2x12x^2 - x - 12 can be factored into (x4)(x+3)(x - 4)(x + 3).
    So, g(x)=(x4)(x+3)x4g(x) = \frac{(x - 4)(x + 3)}{x - 4}
  2. Cancel common factor: Next, we cancel out the common factor (x4)(x - 4) from the numerator and the denominator, as long as x4x \neq 4.
    g(x)=(x+3)g(x) = (x + 3) for x4x \neq 4
    Now, we can define g(4)g(4) by substituting xx with 44.
    g(4)=4+3g(4) = 4 + 3
  3. Define g(4)g(4): Calculate the value of g(4)g(4).g(4)=4+3=7g(4) = 4 + 3 = 7

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