Q. Let g(x)=x3+5x10x when x=0.g is continuous for all real numbers.Find g(0).Choose 1 answer:(A) 0(B) 2(C) 5(D) 10
Evaluate Limit: To find the value of g(0), we need to evaluate the limit of g(x) as x approaches 0, because the function is not defined at x=0 due to division by zero.
Simplify Function: The function g(x) can be simplified by factoring out x in the denominator: g(x)=x(x2+5)10x
Cancel Common Factor: After canceling out the common factor x from the numerator and denominator, we get: g(x)=x2+510
Substitute x=0: Now we can safely substitute x=0 into the simplified function to find g(0):g(0)=(02+5)10=510
Perform Division: Perform the division to find the value of g(0):g(0)=510=2
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