Let f(x)=4x-15. Find each of the following: {:[f(a)=],[2f(a)=],[f(2a)=]:} f(a+2)= f(a)+f(2)=

Substitute a for f(a): To find f(a), substitute a for x in the function f(x) = 4x - 15. f(a) = 4a - 15Multiply by 2: To find 2f(a), multiply the result of f(a) by 2. 2f(a) = 2(4a - 15) = 8a - 30Substitute 2a: To find f(2a), substitute 2a for x in the function f(x) = 4x - 15. f(2a) = 4(2a) - 15 = 8a - 15Substitute a+2: To find f(a+2), substitute (a+2) for x in the function f(x) = 4x - 15. f(a+2) = 4(a+2) - 15 = 4a + 8 - 15 = 4a - 7Find f(a) + f(2): To find f(a) + f(2), first find f(2) by substituting 2 for x in the function f(x) = 4x - 15. f(2) = 4(2) - 15 = 8 - 15 = -7 Now, add f(a) to f(2). f(a) + f(2) = (4a - 15) + (-7) = 4a - 15 - 7 = 4a - 22

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Let
f(x)=4x-15. Find each of the following:

{:[f(a)=],[2f(a)=],[f(2a)=]:}

f(a+2)=

f(a)+f(2)=

Let $f(x)=4 x-15$ . Find each of the following: $\newline$ $\begin{array}{l} f(a)= \\ 2 f(a)= \\ f(2 a)= \end{array}$ $\newline$ $f(a+2)=$ $\newline$ $f(a)+f(2)=$

View step-by-step help

Full solution

Q. Let

f(x)=4 x-15

. Find each of the following:

\newline

\begin{array}{l} f(a)= \\ 2 f(a)= \\ f(2 a)= \end{array}

\newline

f(a+2)=

\newline

f(a)+f(2)=

Substitute $a$ for $f(a)$ : To find $f(a)$ , substitute $a$ for $x$ in the function $f(x) = 4x - 15$ .
$f(a) = 4a - 15$
Multiply by $2$ : To find $2f(a)$ , multiply the result of $f(a)$ by $2$ . $\newline$ $2f(a) = 2(4a - 15) = 8a - 30$
Substitute $2a$ : To find $f(2a)$ , substitute $2a$ for $x$ in the function $f(x) = 4x - 15$ . $\newline$ $f(2a) = 4(2a) - 15 = 8a - 15$
Substitute $a+2$ : To find $f(a+2)$ , substitute $(a+2)$ for $x$ in the function $f(x) = 4x - 15$ . $\newline$ $f(a+2) = 4(a+2) - 15 = 4a + 8 - 15 = 4a - 7$
Find $f(a) + f(2)$ : To find $f(a) + f(2)$ , first find $f(2)$ by substituting $2$ for $x$ in the function $f(x) = 4x - 15$ . $\newline$ $f(2) = 4(2) - 15 = 8 - 15 = -7$ $\newline$ Now, add $f(a)$ to $f(2)$ . $\newline$ $f(a) + f(2) = (4a - 15) + (-7) = 4a - 15 - 7 = 4a - 22$