Let f be a continuous function on the closed interval [−5,0], where f(−5)=0 and f(0)=5.Which of the following is guaranteed by the Intermediate Value Theorem?Choose 1 answer:(A) f(c)=2 for at least one c between −5 and 0(B) f(c)=−2 for at least one c between 0 and 5(C) f(c)=2 for at least one c between 0 and 5(D) f(c)=−2 for at least one c between −5 and 0
Q. Let f be a continuous function on the closed interval [−5,0], where f(−5)=0 and f(0)=5.Which of the following is guaranteed by the Intermediate Value Theorem?Choose 1 answer:(A) f(c)=2 for at least one c between −5 and 0(B) f(c)=−2 for at least one c between 0 and 5(C) f(c)=2 for at least one c between 0 and 5(D) f(c)=−2 for at least one c between −5 and 0
Apply Intermediate Value Theorem: The Intermediate Value Theorem states that if a function f is continuous on a closed interval [a,b] and N is any number between f(a) and f(b), then there exists at least one c in the interval [a,b] such that f(c)=N. We need to apply this theorem to the given function f on the interval [−5,0].
Given Function Values: We are given that f(−5)=0 and f(0)=5. This means that the function f takes on all values between 0 and 5 on the interval [−5,0].
Option (A) Analysis: Option (A) asks if f(c)=2 for at least one c between −5 and 0. Since 2 is between 0 and 5, the Intermediate Value Theorem guarantees that there is at least one c in the interval [−5,0] such that f(c)=2.
Option (B) Analysis: Option (B) asks if f(c)=−2 for at least one c between 0 and 5. This is not applicable because the interval given in the problem is [−5,0], not [0,5].
Option (C) Analysis: Option (C) asks if f(c)=2 for at least one c between 0 and 5. Again, this is not applicable because the interval given in the problem is [−5,0], not [0,5].
Option (D) Analysis: Option (D) asks if f(c)=−2 for at least one c between −5 and 0. Since −2 is not between the values of f(−5)=0 and f(0)=5, the Intermediate Value Theorem does not guarantee that there is a c in the interval [−5,0] such that f(c)=−2.