Let F = {2, 4, 8, 16} and G = {4}. What is F ∪ G? Choices: (A){4} (B){2, 4, 8, 16} (C){2, 8, 16} (D){8, 16}

Understand Union of Sets: First, let's understand what the union of two sets means. The union of two sets F and G, denoted by F ∪ G, is the set of all elements that are in F, or in G, or in both. To find F ∪ G, we simply combine all the unique elements from both sets without repeating any elements.List Elements of Sets: Now, let's list the elements of set F and set G. Set F = {2, 4, 8, 16} and set G = {4}. We can see that the element 4 is present in both sets F and G.Find Union F ∪ G: To find the union F ∪ G, we combine the elements of both sets while keeping only unique elements. Since 4 is already in set F, we do not need to add it again. Therefore, F ∪ G = {2, 4, 8, 16}.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Let $F = \{2, 4, 8, 16\}$ and $G = \{4\}$ . What is $F \cup G$ ? $\newline$ Choices: $\newline$ (A) $\{4\}$ $\newline$ (B) $\{2, 4, 8, 16\}$ $\newline$ (C) $\{2, 8, 16\}$ $\newline$ (D) $\{8, 16\}$

View step-by-step help

Home

Math Problems

Grade 8

Write variable expressions for arithmetic sequences

Full solution

Q. Let

F = \{2, 4, 8, 16\}

and

G = \{4\}

. What is

F \cup G

\newline

Choices:

\newline

(A)

\{4\}

\newline

(B)

\{2, 4, 8, 16\}

\newline

(C)

\{2, 8, 16\}

\newline

(D)

\{8, 16\}

Understand Union of Sets: First, let's understand what the union of two sets means. The union of two sets $F$ and $G$ , denoted by $F \cup G$ , is the set of all elements that are in $F$ , or in $G$ , or in both. To find $F \cup G$ , we simply combine all the unique elements from both sets without repeating any elements.
List Elements of Sets: Now, let's list the elements of set $F$ and set $G$ . Set $F = \{2, 4, 8, 16\}$ and set $G = \{4\}$ . We can see that the element $4$ is present in both sets $F$ and $G$ .
Find Union $F \cup G$ : To find the union $F \cup G$ , we combine the elements of both sets while keeping only unique elements. Since $4$ is already in set $F$ , we do not need to add it again. Therefore, $F \cup G = \{2, 4, 8, 16\}$ .