Q. Let a,b,c be the three rational numbers where a=32b=54 and c=6−5 and Verify:(i) a+(b+c)=(a+b)+c (Associative property of addition)
Calculate Sum of Fractions: First, we will calculate the sum of b and c, and then add a to the result.b+c=(54)+(−65)To add these fractions, we need a common denominator, which is 30. So, we convert the fractions to have the same denominator:b=(54)⋅(66)=(3024)c=(−65)⋅(55)=(−3025)Now, we add b and c:b+c=(3024)+(−3025)=(3024−25)=−301
Add a to the Result: Next, we add a to the result of b+c.a+(b+c)=32+(−301)Again, we need a common denominator, which is 30.So, we convert a to have the same denominator:a=(32)∗(1010)=3020Now, we add a to the result of b+c:a+(b+c)=3020+(−301)=3020−1=3019
Calculate Sum of Fractions: Now, we will calculate the sum of a and b, and then add c to the result.a+b=32+54To add these fractions, we need a common denominator, which is 15.So, we convert the fractions to have the same denominator:a=32×55=1510b=54×33=1512Now, we add a and b:a+b=1510+1512=1510+12=1522
Add c to the Result: Finally, we add c to the result of a+b.(a+b)+c=(1522)+(−65)To add these fractions, we need a common denominator, which is 30. So, we convert the fractions to have the same denominator:(a+b)=(1522)∗(22)=(3044)c=(−65)∗(55)=(−3025)Now, we add (a+b) and c:(a+b)+c=(3044)+(−3025)=3044−25=3019
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