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Last Sunday, the average temperature was 
8% higher than the average temperature two Sundays ago. The average temperature two Sundays ago was 
T degrees Celsius.
Which of the following expressions could represent the average temperature last Sunday?
Choose 2 answers:
A 
1.08 T
B 
T+0.08
c 
T+8
D 
(1+(8)/(100))T
E 
1.8 T

Last Sunday, the average temperature was 8% 8 \% higher than the average temperature two Sundays ago. The average temperature two Sundays ago was T T degrees Celsius.\newlineWhich of the following expressions could represent the average temperature last Sunday?\newlineChoose 22 answers:\newlineA) 1.08T 1.08 T \newlineB) T+0.08 T+0.08 \newlineC) T+8 T+8 \newlineD) (1+8100)T \left(1+\frac{8}{100}\right) T \newlineE) 1.8T 1.8 T

Full solution

Q. Last Sunday, the average temperature was 8% 8 \% higher than the average temperature two Sundays ago. The average temperature two Sundays ago was T T degrees Celsius.\newlineWhich of the following expressions could represent the average temperature last Sunday?\newlineChoose 22 answers:\newlineA) 1.08T 1.08 T \newlineB) T+0.08 T+0.08 \newlineC) T+8 T+8 \newlineD) (1+8100)T \left(1+\frac{8}{100}\right) T \newlineE) 1.8T 1.8 T
  1. Calculate 8%8\% Increase: To find the average temperature last Sunday, which was 8%8\% higher than the average temperature two Sundays ago, we need to increase the temperature from two Sundays ago by 8%8\%. The temperature two Sundays ago is given as TT degrees Celsius.
  2. Convert Percentage to Decimal: An 8%8\% increase can be calculated by multiplying the original amount by 11 plus the percentage increase expressed as a decimal. To convert a percentage to a decimal, we divide by 100100. Therefore, 8%8\% as a decimal is 8100\frac{8}{100} or 0.080.08.
  3. Multiply Original Temperature: Now we multiply the original temperature TT by 1+0.081 + 0.08 to find the new temperature. This gives us T×(1+0.08)T \times (1 + 0.08) which simplifies to T×1.08T \times 1.08.
  4. Check Answer Choices: We can now check the answer choices to see which ones match our expression T×1.08T \times 1.08. Choice A is 1.08T1.08T, which matches our expression exactly.
  5. Identify Correct Representations: Choice D is (1+(8100))T(1 + (\frac{8}{100}))T, which simplifies to (1+0.08)T(1 + 0.08)T, which is also T×1.08T \times 1.08. So, choice D is also a correct representation of the average temperature last Sunday.
  6. Identify Correct Representations: Choice D is (1+(8100))T(1 + (\frac{8}{100}))T, which simplifies to (1+0.08)T(1 + 0.08)T, which is also T×1.08T \times 1.08. So, choice D is also a correct representation of the average temperature last Sunday.Choices B, C, and E do not correctly represent an 8%8\% increase. Choice B is T+0.08T + 0.08, which would only add 0.080.08 degrees to TT, not 8%8\%. Choice C is T+8T + 8, which adds 88 degrees to TT, not 8%8\%. Choice E is (1+0.08)T(1 + 0.08)T22, which would represent an (1+0.08)T(1 + 0.08)T33 increase, not 8%8\%.

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