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Kayla measured a line to be 15 inches long. If the actual length of the line is 16 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer: %

Kayla measured a line to be 1515 inches long. If the actual length of the line is 1616 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?\newlineAnswer: ______% \%

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Q. Kayla measured a line to be 1515 inches long. If the actual length of the line is 1616 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?\newlineAnswer: ______% \%
  1. Understand formula: Understand the percent error formula.\newlinePercent error is calculated using the formula: \newlinePercent Error = (∣ActualValue−MeasuredValue∣/ActualValue)×100%(|Actual Value - Measured Value| / Actual Value) \times 100\%\newlineHere, the Actual Value is 1616 inches and the Measured Value is 1515 inches.
  2. Plug values: Plug the values into the percent error formula.\newlinePercent Error = (∣16−15∣/16)×100%(|16 - 15| / 16) \times 100\%
  3. Calculate difference: Calculate the absolute difference between the actual value and the measured value.\newline∣16−15∣=1|16 - 15| = 1 inch
  4. Divide difference: Divide the absolute difference by the actual value. 116=0.0625\frac{1}{16} = 0.0625
  5. Convert to percentage: Convert the decimal to a percentage. 0.0625×100%=6.25%0.0625 \times 100\% = 6.25\%
  6. Round percent error: Round the percent error to the nearest tenth of a percent. 6.25%6.25\% rounded to the nearest tenth of a percent is 6.3%6.3\%.

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