Kayden measured a line to be 18.1 inches long. If the actual length of the line is 19.2 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer: %

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Kayden measured a line to be 18.1 inches long. If the actual length of the line is 19.2 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer:  %

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Understand percent error formula: Understand the percent error formula. Percent error is calculated using the formula:  Percent Error = (|Actual Value - Measured Value| / Actual Value) × 100 Here, the Actual Value is the true length of the line, and the Measured Value is the length Kayden measured.Plug in given values: Plug in the given values into the percent error formula. Actual Value = 19.2 inches Measured Value = 18.1 inches Percent Error = (|19.2 - 18.1| / 19.2) × 100Calculate absolute difference: Calculate the absolute difference between the Actual Value and the Measured Value. Absolute difference = |19.2 - 18.1| = |1.1| = 1.1Divide by Actual Value: Divide the absolute difference by the Actual Value. Division result = 1.1 / 19.2Perform division for decimal form: Perform the division to find the decimal form of the percent error. Division result = 1.1 / 19.2 ≈ 0.0572916667Convert decimal to percentage: Convert the decimal to a percentage by multiplying by 100. Percent Error = 0.0572916667 × 100 ≈ 5.72916667%Round to nearest tenth: Round the percent error to the nearest tenth of a percent. Rounded Percent Error = 5.7%

Kayden measured a line to be $18$ . $1$ inches long. If the actual length of the line is $19$ . $2$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer: ______ $\%$

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Kayden measured a line to be $18$ . $1$ inches long. If the actual length of the line is $19$ . $2$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer: ______ $\%$