Kajal tried to solve the differential equation dxdy=−x2y2. This is her work:dxdy=−x2y2Step 1: ∫−y−2dy=∫x2dxStep 2: y−1=3x3+CStep 3: y=x33+CIs Kajal's work correct? If not, what is her mistake?Choose 1 answer:(A) Kajal's work is correct.(B) Step 1 is incorrect. The separation of variables wasn't done correctly.(C) Step 2 is incorrect. Kajal didn't integrate x2 correctly.(D) Step 3 is incorrect. Kajal didn't take the reciprocal of 3x3+C correctly.
Q. Kajal tried to solve the differential equation dxdy=−x2y2. This is her work:dxdy=−x2y2Step 1: ∫−y−2dy=∫x2dxStep 2: y−1=3x3+CStep 3: y=x33+CIs Kajal's work correct? If not, what is her mistake?Choose 1 answer:(A) Kajal's work is correct.(B) Step 1 is incorrect. The separation of variables wasn't done correctly.(C) Step 2 is incorrect. Kajal didn't integrate x2 correctly.(D) Step 3 is incorrect. Kajal didn't take the reciprocal of 3x3+C correctly.
Check Separation of Variables: Kajal is attempting to solve the differential equation by separating variables. Let's check if the separation of variables in Step 1 is done correctly. The original equation is:(dxdy)=−x2y2To separate the variables, we should divide both sides by y2 and multiply both sides by dx to get:y21dy=−x2dxNow, we integrate both sides:∫(y21)dy=∫(−x2)dxThis looks like what Kajal has written, so Step 1 seems to be correct.
Integrate Both Sides: Now, let's perform the integration on both sides. For the left side, the integral of y21 with respect to y is −y1. For the right side, the integral of −x2 with respect to x is −3x3. So we have:−y1=−3x3+CKajal's integration result for y−1 is correct, but she missed the negative sign on the right side of the equation.
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