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Josue is saving money and plans on making quarterly contributions into an account earning a quarterly interest rate of 
1.875%. If Josue would like to end up with 
$95,000 after 15 years, how much does he need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Josue is saving money and plans on making quarterly contributions into an account earning a quarterly interest rate of 1.875% 1.875 \% . If Josue would like to end up with $95,000 \$ 95,000 after 1515 years, how much does he need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Josue is saving money and plans on making quarterly contributions into an account earning a quarterly interest rate of 1.875% 1.875 \% . If Josue would like to end up with $95,000 \$ 95,000 after 1515 years, how much does he need to contribute to the account every quarter, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Given Values: Identify the given values from the problem.\newlineAA (future value of the account) = $95,000\$95,000\newlineii (interest rate per period) = 1.875%1.875\% or 0.018750.01875 when converted to decimal\newlinenn (number of periods) = 1515 years * 44 quarters/year = 6060 quarters\newlineNow we can use these values in the formula provided.
  2. Substitute Values into Formula: Substitute the given values into the formula.\newlineWe have the formula A=d×((1+i)n1i)A = d \times \left(\frac{(1 + i)^{n} - 1}{i}\right), where AA is the future value, dd is the amount invested each period, ii is the interest rate per period, and nn is the number of periods.\newlineLet's plug in the values:\newline$95,000=d×((1+0.01875)6010.01875)\$95,000 = d \times \left(\frac{(1 + 0.01875)^{60} - 1}{0.01875}\right)
  3. Calculate Compound Factor: Calculate the compound factor.\newlineFirst, calculate (1+i)n(1 + i)^n:\newline(1+0.01875)60(1 + 0.01875)^{60}\newlineNow, use a calculator to find the value.
  4. Continue Calculation: Continue the calculation from the previous step.\newlineUsing a calculator, we find:\newline(1+0.01875)602.45489(1 + 0.01875)^{60} \approx 2.45489\newlineNow we can update our equation:\newline$95,000=d×(2.4548910.01875)\$95,000 = d \times \left(\frac{2.45489 - 1}{0.01875}\right)
  5. Simplify Equation: Simplify the equation further.\newlineSubtract 11 from 22.4548945489:\newline2.454891=1.454892.45489 - 1 = 1.45489\newlineNow, divide by the interest rate:\newline1.454890.0187577.59413\frac{1.45489}{0.01875} \approx 77.59413\newlineUpdate the equation with this value:\newline$95,000=d×77.59413\$95,000 = d \times 77.59413
  6. Solve for Amount Invested: Solve for dd, the amount invested each period.\newlineTo find dd, divide the future value by the compound factor:\newlined=$95,00077.59413d = \frac{\$95,000}{77.59413}\newlineUse a calculator to find dd.
  7. Calculate and Round Value: Calculate the value of dd and round to the nearest dollar.\newlineUsing a calculator, we find:\newlined$(95,000)/77.59413$(1224.14)d \approx \$(95,000) / 77.59413 \approx \$(1224.14)\newlineSince we need to round to the nearest dollar, d$(1224)d \approx \$(1224).

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