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Josiah is saving money and plans on making monthly contributions into an account earning a monthly interest rate of 
0.35%. If Josiah would like to end up with 
$12,000 after 5 years, how much does he need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Josiah is saving money and plans on making monthly contributions into an account earning a monthly interest rate of 0.35% 0.35 \% . If Josiah would like to end up with $12,000 \$ 12,000 after 55 years, how much does he need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Josiah is saving money and plans on making monthly contributions into an account earning a monthly interest rate of 0.35% 0.35 \% . If Josiah would like to end up with $12,000 \$ 12,000 after 55 years, how much does he need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Given Values: Identify the given values from the problem.\newlineAA (future value of the account) = $12,000\$12,000\newlineii (interest rate per period) = 0.35%0.35\% per month\newlinenn (number of periods) = 55 years 12* 12 months/year = 6060 months\newlineWe will use the formula A=d((1+i)n1i)A = d * \left(\frac{(1 + i)^{n} - 1}{i}\right) to find dd, the amount invested at the end of each period.
  2. Convert Interest Rate: Convert the interest rate from a percentage to a decimal. i=0.35%=0.35100=0.0035i = 0.35\% = \frac{0.35}{100} = 0.0035
  3. Substitute Values into Formula: Substitute the values into the formula.\newlineA=$12,000A = \$12,000\newlinei=0.0035i = 0.0035\newlinen=60n = 60\newlineNow we will plug these values into the formula to solve for dd.
  4. Calculate Value Inside Parentheses: Calculate the value inside the parentheses.\newline(1+i)n=(1+0.0035)60(1 + i)^n = (1 + 0.0035)^{60}\newlineUse a calculator to find the value.\newline(1+0.0035)601.229678(1 + 0.0035)^{60} \approx 1.229678
  5. Calculate Numerator: Calculate the numerator of the formula. ((1+i)n1)=1.2296781=0.229678((1 + i)^n - 1) = 1.229678 - 1 = 0.229678
  6. Calculate Denominator: Calculate the denominator of the formula.\newlinei=0.0035i = 0.0035
  7. Calculate Fraction Value: Calculate the value of the fraction in the formula. 0.229678/0.003565.62285710.229678 / 0.0035 \approx 65.6228571
  8. Calculate Monthly Contribution: Calculate the monthly contribution dd.A=$12,000A = \$12,000d=A(0.229678/0.0035)d = \frac{A}{(0.229678 / 0.0035)}d=$12,00065.6228571d = \frac{\$12,000}{65.6228571}d$182.88d \approx \$182.88
  9. Round Monthly Contribution: Round the monthly contribution to the nearest dollar. d$(183)d \approx \$(183)

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