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Jose deposits 
$7,500 every year into an account earning an annual interest rate of 
5.9% compounded annually. How much would he have in the account after 10 years, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Jose deposits $7,500 \$ 7,500 every year into an account earning an annual interest rate of 5.9% 5.9 \% compounded annually. How much would he have in the account after 1010 years, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Jose deposits $7,500 \$ 7,500 every year into an account earning an annual interest rate of 5.9% 5.9 \% compounded annually. How much would he have in the account after 1010 years, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Given Values: Identify the given values from the problem.\newlineWe are given:\newlinedd (the amount invested at the end of each period) = $7,500\$7,500\newlineii (the interest rate per period) = 5.9%5.9\% or 0.0590.059 when converted to decimal\newlinenn (the number of periods) = 1010 years\newlineWe will use these values in the compound interest formula to find AA (the future value of the account).
  2. Convert Interest Rate: Convert the annual interest rate from a percentage to a decimal.\newlineTo convert 5.9%5.9\% to a decimal, divide by 100100.\newlinei=5.9%100=0.059i = \frac{5.9\%}{100} = 0.059
  3. Substitute Values in Formula: Substitute the values into the compound interest formula.\newlineUsing the formula A=d×((1+i)n1)/iA = d \times \left(\left(1 + i\right)^{n} - 1\right) / i, we substitute the values we have:\newlineA=$(7,500)×((1+0.059)101)/0.059A = \$(7,500) \times \left(\left(1 + 0.059\right)^{10} - 1\right) / 0.059
  4. Calculate Exponential Value: Calculate the value inside the parentheses (1+i)n(1 + i)^{n}.(1+0.059)10=(1.059)10(1 + 0.059)^{10} = (1.059)^{10} Now, calculate the exponentiation.(1.059)101.77729(1.059)^{10} \approx 1.77729 (rounded to five decimal places for precision in further calculations)
  5. Subtract One: Continue with the formula by subtracting 11 from the result obtained in Step 44.\newline1.777291=0.777291.77729 - 1 = 0.77729
  6. Divide by Interest Rate: Divide the result from Step 55 by the interest rate ii.\newline0.77729/0.05913.175590.77729 / 0.059 \approx 13.17559
  7. Multiply by Amount: Multiply the result from Step 66 by the amount invested at the end of each period dd.$7,500×13.17559$98,817.42\$7,500 \times 13.17559 \approx \$98,817.42
  8. Round Final Result: Round the final result to the nearest dollar.\newlineThe future value of the account, rounded to the nearest dollar, is approximately $98,817\$98,817.

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