Jocelyn measured a line to be 12.5 inches long. If the actual length of the line is 12.4 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer: %

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Jocelyn measured a line to be 12.5 inches long. If the actual length of the line is 12.4 inches, then what was the percent error of the measurement, to the nearest tenth of a percent? Answer:  %

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Understand formula for percent error: Understand the formula for percent error. The formula for percent error is:  Percent Error = (|Measured Value - Actual Value| / Actual Value) × 100% Here, the measured value is 12.5 inches, and the actual value is 12.4 inches.Plug values into formula: Plug the values into the percent error formula. Percent Error = (|12.5 - 12.4| / 12.4) × 100%Calculate absolute difference: Calculate the absolute difference between the measured value and the actual value. Absolute difference = |12.5 - 12.4| = 0.1 inchDivide difference by actual value: Divide the absolute difference by the actual value. Division result = 0.1 / 12.4Perform division for decimal form: Perform the division to find the decimal form of the percent error. Division result = 0.008064516129032258 (rounded to more decimal places for accuracy)Convert decimal to percentage: Convert the decimal to a percentage. Percent Error = 0.008064516129032258 × 100% = 0.8064516129032258%Round percent error: Round the percent error to the nearest tenth of a percent. Rounded Percent Error = 0.8%

Jocelyn measured a line to be $12$ . $5$ inches long. If the actual length of the line is $12$ . $4$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer: ________ $\%$

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Jocelyn measured a line to be $12$ . $5$ inches long. If the actual length of the line is $12$ . $4$ inches, then what was the percent error of the measurement, to the nearest tenth of a percent? $\newline$ Answer: ________ $\%$