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Andy has $100 in an account. The interest rate is 6% compounded annually.
To the nearest cent, how much will he have in 2 years?
Use the formula B=p(1+r)^(t), where B is the balance (final amount), p is the principal (starting amount), r is the interest rate expressed as a decimal, and t is the time in years.
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Andy has $100 \$ 100 in an account. The interest rate is 6% 6 \% compounded annually.\newlineTo the nearest cent, how much will he have in 22 years?\newlineUse the formula B=p(1+r)t B=p(1+r)^{t} , where B B is the balance (final amount), p p is the principal (starting amount), r r is the interest rate expressed as a decimal, and t t is the time in years.\newline$ \$ \square

Full solution

Q. Andy has $100 \$ 100 in an account. The interest rate is 6% 6 \% compounded annually.\newlineTo the nearest cent, how much will he have in 22 years?\newlineUse the formula B=p(1+r)t B=p(1+r)^{t} , where B B is the balance (final amount), p p is the principal (starting amount), r r is the interest rate expressed as a decimal, and t t is the time in years.\newline$ \$ \square
  1. Identify values: question_prompt: How much will Andy have in his account after 22 years with an annual compound interest rate of 6%6\%?
  2. Plug values into formula: Step 11: Identify the values for the formula B=p(1+r)tB=p(1+r)^t. Here, p=$100p=\$100, r=6%r=6\% or 0.060.06 as a decimal, and t=2t=2 years.
  3. Calculate (1+0.06)(1+0.06): Step 22: Plug the values into the formula. So, B=100(1+0.06)2B=100(1+0.06)^2.
  4. Raise to power: Step 33: Calculate (1+0.06)(1+0.06) which is 1.061.06.
  5. Multiply principal amount: Step 44: Now raise 1.061.06 to the power of 22. So, 1.0621.06^2 is 1.12361.1236.
  6. Multiply principal amount: Step 44: Now raise 1.061.06 to the power of 22. So, 1.0621.06^2 is 1.12361.1236. Step 55: Multiply the principal amount by the result from step 44. So, 100×1.1236100 \times 1.1236 is 112.36112.36.

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