Is–21/2anirrationalnumber? Choices: (A)yes (B)no

Understand the number: Understand the given number. The given number is –21/2, which is a fraction.Check simplest form: Determine if the fraction is in simplest form. The fraction –21/2 is already in simplest form, with a numerator of –21 and a denominator of 2.Analyze for rational number: Analyze the fraction to see if it is a rational number. A rational number is any number that can be expressed as the quotient or fraction p/q of two integers, with the denominator q not equal to zero. Since –21 and 2 are both integers and 2 is not zero, –21/2 is a rational number.Conclude rational or irrational: Conclude whether –21/2 is an irrational number. Since –21/2 is a rational number, it cannot be an irrational number. Therefore, the answer to whether –21/2 is an irrational number is ＂no.＂

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Is $-\frac{21}{2}$ an irrational number? $\newline$ Choices: $\newline$ (A) yes $\newline$ (B) no

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Math Problems

Grade 8

Identify rational and irrational numbers

Full solution

Q. Is

-\frac{21}{2}

an irrational number?

\newline

Choices:

\newline

(A) yes

\newline

(B) no

Understand the number: Understand the given number. $\newline$ The given number is $-\frac{21}{2}$ , which is a fraction.
Check simplest form: Determine if the fraction is in simplest form. $\newline$ The fraction $-\frac{21}{2}$ is already in simplest form, with a numerator of $-21$ and a denominator of $2$ .
Analyze for rational number: Analyze the fraction to see if it is a rational number. $\newline$ A rational number is any number that can be expressed as the quotient or fraction $\frac{p}{q}$ of two integers, with the denominator $q$ not equal to zero. Since $–21$ and $2$ are both integers and $2$ is not zero, $–\frac{21}{2}$ is a rational number.
Conclude rational or irrational: Conclude whether $\frac{-21}{2}$ is an irrational number. $\newline$ Since $\frac{-21}{2}$ is a rational number, it cannot be an irrational number. Therefore, the answer to whether $\frac{-21}{2}$ is an irrational number is ＂no.＂