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x2+3dx\int x^{2} + 3 \, dx

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Q. x2+3dx\int x^{2} + 3 \, dx
  1. Recognize the integral: Recognize the integral to be solved.\newlineThe integral given is (x2+3)dx\int(x^2 + 3)\,dx. This is an indefinite integral of a polynomial function.
  2. Apply power rule: Apply the power rule for integration to the term x2x^2. The power rule for integration states that xndx=xn+1n+1+C\int x^n \, dx = \frac{x^{n+1}}{n+1} + C, where CC is the constant of integration. For the term x2x^2, n=2n = 2, so we get x2dx=x2+12+1=x33\int x^2 \, dx = \frac{x^{2+1}}{2+1} = \frac{x^3}{3}.
  3. Integrate constant term: Integrate the constant term 33. The integral of a constant aa with respect to xx is ax+Cax + C, where CC is the constant of integration. For the term 33, we get 3dx=3x+C\int 3 \, dx = 3x + C.
  4. Combine results: Combine the results from Step 22 and Step 33.\newlineThe integral of the entire expression (x2+3)dx\int(x^2 + 3)\,dx is the sum of the integrals of its terms.\newlineSo, (x2+3)dx=x33+3x+C\int(x^2 + 3)\,dx = \frac{x^3}{3} + 3x + C.
  5. Write final answer: Write the final answer.\newlineThe final answer is the antiderivative of the given function.\newlinex33+=""3x=""c\frac{x^3}{3} +="" 3x="" c="">

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