(1)/(3)×(2)/(5)+(4)/(5)×(1)/(5)-(1)/(2)×(3)/(5)

Calculate Fraction Products: Calculate the value of (1/3)×(2/5). To find the product of two fractions, multiply the numerators together and the denominators together. (1/3)×(2/5) = (1×2)/(3×5) = 2/15Add and Subtract Fractions: Calculate the value of (4/5)×(1/5). Similarly, multiply the numerators and the denominators. (4/5)×(1/5) = (4×1)/(5×5) = 4/25Calculate the value of (1/2)×(3/5). Again, multiply the numerators and the denominators. (1/2)×(3/5) = (1×3)/(2×5) = 3/10Add the results from Step 1 and Step 2, then subtract the result from Step 3. Add 2/15 and 4/25, then subtract 3/10. To add or subtract fractions, they must have a common denominator. The least common denominator (LCD) for 15, 25, and 10 is 150. Convert each fraction to an equivalent fraction with a denominator of 150. 2/15 = (2×10)/(15×10) = 20/150 4/25 = (4×6)/(25×6) = 24/150 3/10 = (3×15)/(10×15) = 45/150 Now perform the addition and subtraction: (20/150 + 24/150) - 45/150 = (44/150) - 45/150 = -1/150

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(1)/(3)×(2)/(5)+(4)/(5)×(1)/(5)-(1)/(2)×(3)/(5)

$\frac{1}{3} \times \frac{2}{5}+\frac{4}{5} \times \frac{1}{5}-\frac{1}{2} \times \frac{3}{5}$

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Algebra 2

Sum of finite series not start from 1

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\frac{1}{3} \times \frac{2}{5}+\frac{4}{5} \times \frac{1}{5}-\frac{1}{2} \times \frac{3}{5}

Calculate Fraction Products: Calculate the value of $(\frac{1}{3})\times(\frac{2}{5})$ . To find the product of two fractions, multiply the numerators together and the denominators together. $(\frac{1}{3})\times(\frac{2}{5}) = (\frac{1\times2}{3\times5}) = \frac{2}{15}$
Add and Subtract Fractions: Calculate the value of $(\frac{4}{5})\times(\frac{1}{5})$ . Similarly, multiply the numerators and the denominators. $(\frac{4}{5})\times(\frac{1}{5}) = (\frac{4\times1}{5\times5}) = \frac{4}{25}$
Add and Subtract Fractions: Calculate the value of $(\frac{4}{5})\times(\frac{1}{5})$ . Similarly, multiply the numerators and the denominators. $(\frac{4}{5})\times(\frac{1}{5}) = (\frac{4\times1}{5\times5}) = \frac{4}{25}$ Calculate the value of $(\frac{1}{2})\times(\frac{3}{5})$ . Again, multiply the numerators and the denominators. $(\frac{1}{2})\times(\frac{3}{5}) = (\frac{1\times3}{2\times5}) = \frac{3}{10}$
Add and Subtract Fractions: Calculate the value of $(\frac{4}{5})\times(\frac{1}{5})$ . Similarly, multiply the numerators and the denominators. $(\frac{4}{5})\times(\frac{1}{5}) = (\frac{4\times1}{5\times5}) = \frac{4}{25}$ Calculate the value of $(\frac{1}{2})\times(\frac{3}{5})$ . Again, multiply the numerators and the denominators. $(\frac{1}{2})\times(\frac{3}{5}) = (\frac{1\times3}{2\times5}) = \frac{3}{10}$ Add the results from Step $1$ and Step $2$ , then subtract the result from Step $3$ . Add $\frac{2}{15}$ and $\frac{4}{25}$ , then subtract $\frac{3}{10}$ . To add or subtract fractions, they must have a common denominator. The least common denominator (LCD) for $15$ , $25$ , and $10$ is $150$ . Convert each fraction to an equivalent fraction with a denominator of $150$ . $\frac{2}{15} = (\frac{2\times10}{15\times10}) = \frac{20}{150}$ $\frac{4}{25} = (\frac{4\times6}{25\times6}) = \frac{24}{150}$ $\frac{3}{10} = (\frac{3\times15}{10\times15}) = \frac{45}{150}$ Now perform the addition and subtraction: $(\frac{4}{5})\times(\frac{1}{5}) = (\frac{4\times1}{5\times5}) = \frac{4}{25}$ $0$