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In 
DeltaKLM,m=98 inches, 
l=95 inches and 
/_L=114^(@). Find all possible values of 
/_M, to the nearest degree.
Answer:

In ΔKLM,m=98 \Delta \mathrm{KLM}, m=98 inches, l=95 l=95 inches and L=114 \angle \mathrm{L}=114^{\circ} . Find all possible values of M \angle \mathrm{M} , to the nearest degree.\newlineAnswer:

Full solution

Q. In ΔKLM,m=98 \Delta \mathrm{KLM}, m=98 inches, l=95 l=95 inches and L=114 \angle \mathrm{L}=114^{\circ} . Find all possible values of M \angle \mathrm{M} , to the nearest degree.\newlineAnswer:
  1. Apply Law of Sines: Use the Law of Sines to find the ratio of the sides to the sines of their opposite angles.\newlineThe Law of Sines states that in any triangle, the ratio of the length of a side to the sine of its opposite angle is constant. That is, for triangle KLM:\newlinemsin(M)=lsin(L)\frac{m}{\sin(M)} = \frac{l}{\sin(L)}
  2. Substitute Given Values: Substitute the given values into the Law of Sines.\newlineWe have m=98m = 98 inches, l=95l = 95 inches, and angle L=114L = 114 degrees. Plugging these into the equation from Step 11 gives us:\newline98sin(M)=95sin(114°)\frac{98}{\sin(M)} = \frac{95}{\sin(114°)}
  3. Solve for sin(M): Solve for sin(M). First, calculate sin(114)\sin(114^\circ) using a calculator: sin(114)0.913545\sin(114^\circ) \approx 0.913545 Now, rearrange the equation to solve for sin(M)\sin(M): sin(M)=98×sin(114)95\sin(M) = \frac{98 \times \sin(114^\circ)}{95} sin(M)98×0.91354595\sin(M) \approx \frac{98 \times 0.913545}{95} sin(M)89.4674195\sin(M) \approx \frac{89.46741}{95} sin(M)0.9417622\sin(M) \approx 0.9417622
  4. Find Angle M: Find the angle MM whose sine is approximately 0.94176220.9417622. Using a calculator, we find the inverse sine (arcsin) of 0.94176220.9417622: Marcsin(0.9417622)M \approx \arcsin(0.9417622) M70.53M \approx 70.53^\circ
  5. Check for Second Solution: Check if there is a second possible value for angle MM. Since the sine function is positive in both the first and second quadrants, and the sum of angles in a triangle must be 180180 degrees, we must check if there is another possible angle MM that is less than 180°114°=66°180° - 114° = 66°. Since 70.53°70.53° is already greater than 66°66°, there is no second solution within the triangle's angle constraints.
  6. Round Angle MM: Round the value of angle MM to the nearest degree.M71M \approx 71^\circ (to the nearest degree)

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