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In 
DeltaKLM,m=55 inches, 
l=49 inches and 
/_L=121^(@). Find all possible values of 
/_M, to the nearest degree.
Answer:

In ΔKLM,m=55 \Delta \mathrm{KLM}, m=55 inches, l=49 l=49 inches and L=121 \angle \mathrm{L}=121^{\circ} . Find all possible values of M \angle \mathrm{M} , to the nearest degree.\newlineAnswer:

Full solution

Q. In ΔKLM,m=55 \Delta \mathrm{KLM}, m=55 inches, l=49 l=49 inches and L=121 \angle \mathrm{L}=121^{\circ} . Find all possible values of M \angle \mathrm{M} , to the nearest degree.\newlineAnswer:
  1. Apply Law of Sines: Use the Law of Sines to find the ratio of the sides to the sines of their opposite angles.\newlineThe Law of Sines states that in any triangle, the ratio of the length of a side to the sine of its opposite angle is constant. That is, for triangle KLM:\newlinemsin(M)=lsin(L)\frac{m}{\sin(M)} = \frac{l}{\sin(L)}
  2. Substitute Given Values: Substitute the given values into the Law of Sines.\newlineWe have m=55m = 55 inches, l=49l = 49 inches, and angle L=121L = 121 degrees. Plugging these into the equation from Step 11 gives us:\newline55sin(M)=49sin(121)\frac{55}{\sin(M)} = \frac{49}{\sin(121^\circ)}
  3. Solve for sin(M)\sin(M): Solve for sin(M)\sin(M). First, calculate sin(121°)\sin(121°). Since 121°121° is in the second quadrant, where sine is positive, we can use a calculator to find: sin(121°)0.8572\sin(121°) \approx 0.8572 Now, we can rearrange the equation to solve for sin(M)\sin(M): sin(M)=55×sin(121°)49\sin(M) = \frac{55 \times \sin(121°)}{49} sin(M)55×0.857249\sin(M) \approx \frac{55 \times 0.8572}{49} sin(M)47.14649\sin(M) \approx \frac{47.146}{49} sin(M)0.9624\sin(M) \approx 0.9624
  4. Find Angle MM: Find the angle MM whose sine is approximately 0.96240.9624. Using a calculator, we find that: Msin1(0.9624)M \approx \sin^{-1}(0.9624) M74.5M \approx 74.5^\circ (to the nearest degree)
  5. Check for Second Solution: Check for possible second solution.\newlineSince the sine function is positive in both the first and second quadrants, there could be another possible value for angle MM in the second quadrant. However, since angle LL is already 121121 degrees and the sum of angles in a triangle must be 180180 degrees, there is not enough degrees left for angle MM to be in the second quadrant. Therefore, there is only one possible solution for angle MM.
  6. Verify Angle Sum: Verify that the sum of angles in triangle KLM is 180180 degrees.\newlineAngle K=180(Angle L+Angle M)K = 180^\circ - (\text{Angle } L + \text{Angle } M)\newlineAngle K=180(121+74.5)K = 180^\circ - (121^\circ + 74.5^\circ)\newlineAngle K=180195.5K = 180^\circ - 195.5^\circ\newlineThis would give a negative value for angle KK, which is not possible. Therefore, we must have made a rounding error in Step 44. We need to find the exact value of angle MM without rounding to ensure the sum of angles is 180180 degrees.

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