In a newspaper, it was reported that yearly robberies in Springfield were down 50% to 35 in 2011 from 2010. How many robberies were there in Springfield in 2010? Answer:

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In a newspaper, it was reported that yearly robberies in Springfield were down  50% to 35 in 2011 from 2010. How many robberies were there in Springfield in 2010? Answer:

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Understand Problem: Understand the problem and identify the given information. We know that the number of robberies in Springfield in 2011 was 35, which is 50% less than the number of robberies in 2010. We need to find the number of robberies in 2010.Set Up Equation: Set up the equation to find the number of robberies in 2010. Let the number of robberies in 2010 be x. According to the problem, the number of robberies in 2011 is 50% less than that in 2010. This means that the number of robberies in 2011 is 50% of x, which is equal to 35. So, we have the equation: 0.5 * x = 35Solve Equation: Solve the equation for x to find the number of robberies in 2010. Divide both sides of the equation by 0.5 to isolate x: x = 35 / 0.5 x = 70Verify Solution: Verify the solution. If there were 70 robberies in 2010, then a 50% reduction would indeed result in 35 robberies in 2011, because 70 * 0.5 = 35. This confirms that our solution is correct.

In a newspaper, it was reported that yearly robberies in Springfield were down $50 \%$ to $35$ in $2011$ from $2010$ . How many robberies were there in Springfield in $2010$ ? $\newline$ Answer:

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In a newspaper, it was reported that yearly robberies in Springfield were down 50% 50 \% 50% to 353535 in 201120112011 from 201020102010. How many robberies were there in Springfield in 201020102010?\newlineAnswer:

In a newspaper, it was reported that yearly robberies in Springfield were down $50 \%$ to $35$ in $2011$ from $2010$ . How many robberies were there in Springfield in $2010$ ? $\newline$ Answer: