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In a newspaper, it was reported that yearly robberies in Springfield were up 6% to 265 in 2012 from 2011. How many robberies were there in Springfield in 2011? Answer:

In a newspaper, it was reported that yearly robberies in Springfield were up 6% 6 \% to 265265 in 20122012 from 20112011. How many robberies were there in Springfield in 20112011?\newlineAnswer:

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Q. In a newspaper, it was reported that yearly robberies in Springfield were up 6% 6 \% to 265265 in 20122012 from 20112011. How many robberies were there in Springfield in 20112011?\newlineAnswer:
  1. Identify Unknown Variable: To find the number of robberies in 20112011, we need to work backwards from the 20122012 figure, taking into account the 66% increase. We can represent the number of robberies in 20112011 as xx. The number of robberies in 20122012 is then x+0.06xx + 0.06x (which is xx plus 66% of xx). We know that x+0.06xx + 0.06x equals 265265.
  2. Combine Like Terms: Combine like terms to simplify the equation. The equation x+0.06x=265x + 0.06x = 265 can be rewritten as 1.06x=2651.06x = 265 because x+0.06xx + 0.06x is the same as 1x+0.06x1x + 0.06x, which equals 1.06x1.06x.
  3. Solve for Unknown Variable: Now, solve for xx by dividing both sides of the equation by 1.061.06. This will give us the number of robberies in 20112011.x=2651.06x = \frac{265}{1.06}
  4. Perform Division: Perform the division to find the value of xx.x=250x = 250This means there were 250250 robberies in Springfield in 20112011.

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