In a newspaper, it was reported that yearly robberies in Springfield were down 25% to 108 in 2013 from 2012. How many robberies were there in Springfield in 2012? Answer:

Question

In a newspaper, it was reported that yearly robberies in Springfield were down  25% to 108 in 2013 from 2012. How many robberies were there in Springfield in 2012? Answer:

Bytelearn · Accepted Answer

Identify Given Information: Let's identify the given information and what we need to find. We know that the number of robberies in 2013 was 108, which is 25% less than the number of robberies in 2012. We need to find the original number of robberies in 2012 before the decrease.Calculate Percentage Decrease: To find the number of robberies in 2012, we need to understand that a 25% decrease means that the number of robberies in 2013 is 75% of the number of robberies in 2012. Let's represent the number of robberies in 2012 as 'R'.Set Up Equation: We can set up the equation: 75% of R = 108. To solve for R, we need to convert the percentage to a decimal. So, 75% becomes 0.75. The equation is now: 0.75 * R = 108.Solve for R: To find R, we divide both sides of the equation by 0.75. So, R = 108 / 0.75.Final Result: Performing the division, we get R = 144. This means there were 144 robberies in Springfield in 2012.

In a newspaper, it was reported that yearly robberies in Springfield were down $25 \%$ to $108$ in $2013$ from $2012$ . How many robberies were there in Springfield in $2012$ ? $\newline$ Answer:

Full solution

More problems from Percent of change: word problems

Related topics

In a newspaper, it was reported that yearly robberies in Springfield were down 25% 25 \% 25% to 108108108 in 201320132013 from 201220122012. How many robberies were there in Springfield in 201220122012?\newlineAnswer:

In a newspaper, it was reported that yearly robberies in Springfield were down $25 \%$ to $108$ in $2013$ from $2012$ . How many robberies were there in Springfield in $2012$ ? $\newline$ Answer: