In a newspaper, it was reported that the number of yearly robberies in Springfield in 2010 was 135 , and then went up by 20% in 2011 . How many robberies were there in Springfield in 2011? Answer:

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In a newspaper, it was reported that the number of yearly robberies in Springfield in 2010 was 135 , and then went up by  20% in 2011 . How many robberies were there in Springfield in 2011? Answer:

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Understand Problem: Understand the problem and identify the given values. We know that the number of robberies in Springfield in 2010 was 135. We also know that there was a 20% increase in the number of robberies in 2011.Calculate Increase: Calculate the increase in the number of robberies. To find the increase, we multiply the number of robberies in 2010 by the percentage increase (expressed as a decimal). Increase = 135 robberies × 20% (or 0.20 as a decimal).Perform Calculation: Perform the calculation for the increase. Increase = 135 × 0.20 = 27 robberies.Total Robberies 2011: Calculate the total number of robberies in 2011. To find the total number of robberies in 2011, we add the increase to the number of robberies in 2010. Total robberies in 2011 = 135 robberies + 27 robberies.Perform Calculation: Perform the calculation for the total number of robberies in 2011. Total robberies in 2011 = 135 + 27 = 162 robberies.

In a newspaper, it was reported that the number of yearly robberies in Springfield in $2010$ was $135$ , and then went up by $20 \%$ in $2011$ . How many robberies were there in Springfield in $2011$ ? $\newline$ Answer:

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In a newspaper, it was reported that the number of yearly robberies in Springfield in 201020102010 was 135135135 , and then went up by 20% 20 \% 20% in 201120112011 . How many robberies were there in Springfield in 201120112011?\newlineAnswer:

In a newspaper, it was reported that the number of yearly robberies in Springfield in $2010$ was $135$ , and then went up by $20 \%$ in $2011$ . How many robberies were there in Springfield in $2011$ ? $\newline$ Answer: