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Simplify the expression below and write your final expression.

(6x^(2)-384)/(2x^(2)-36 x+160)*(x-10)/(x^(2)+12 x+32)

Simplify the expression below and write your final expression. \newline6x23842x236x+160x10x2+12x+32 \frac{6 x^{2}-384}{2 x^{2}-36 x+160} \cdot \frac{x-10}{x^{2}+12 x+32}

Full solution

Q. Simplify the expression below and write your final expression. \newline6x23842x236x+160x10x2+12x+32 \frac{6 x^{2}-384}{2 x^{2}-36 x+160} \cdot \frac{x-10}{x^{2}+12 x+32}
  1. Factor Numerator: Factor the numerator of the first fraction 6x23846x^2 - 384. To factor out the greatest common factor, we look for the largest number that divides both terms and any common variables. In this case, the greatest common factor is 66. 6x2384=6(x264)6x^2 - 384 = 6(x^2 - 64) Notice that x264x^2 - 64 is a difference of squares and can be factored further. x264=(x+8)(x8)x^2 - 64 = (x + 8)(x - 8) So the fully factored numerator is 6(x+8)(x8)6(x + 8)(x - 8).
  2. Factor Denominator: Factor the denominator of the first fraction 2x236x+1602x^2 - 36x + 160. We look for two numbers that multiply to 2×160=3202\times160 = 320 and add up to 36-36. These numbers are 20-20 and 16-16. So we can write the denominator as: 2x236x+160=2(x218x+80)2x^2 - 36x + 160 = 2(x^2 - 18x + 80) Now we factor the quadratic x218x+80x^2 - 18x + 80 further: x218x+80=(x10)(x8)x^2 - 18x + 80 = (x - 10)(x - 8) So the fully factored denominator is 2(x10)(x8)2(x - 10)(x - 8).
  3. Factor Numerator: Factor the numerator of the second fraction x10x - 10. This is already factored, so we leave it as is.
  4. Factor Denominator: Factor the denominator of the second fraction x2+12x+32x^2 + 12x + 32. We look for two numbers that multiply to 3232 and add up to 1212. These numbers are 44 and 88. So we can write the denominator as: x2+12x+32=(x+4)(x+8)x^2 + 12x + 32 = (x + 4)(x + 8)
  5. Combine and Cancel: Combine the factored forms of the numerators and denominators to rewrite the original expression. 6(x+8)(x8)2(x10)(x8)x10(x+4)(x+8)\frac{6(x + 8)(x - 8)}{2(x - 10)(x - 8)}\cdot\frac{x - 10}{(x + 4)(x + 8)}
  6. Simplify Expression: Cancel out common factors from the numerators and denominators.\newlineThe (x8)(x - 8) term cancels out from the first fraction's numerator and denominator.\newlineThe (x10)(x - 10) term cancels out from the second fraction's numerator and the first fraction's denominator.\newlineThe (x+8)(x + 8) term cancels out from the first fraction's numerator and the second fraction's denominator.\newlineAfter canceling, we are left with:\newline62(x+4)\frac{6}{2(x + 4)}\cdot1x+4\frac{1}{x + 4}
  7. Simplify Expression: Cancel out common factors from the numerators and denominators.\newlineThe (x8)(x - 8) term cancels out from the first fraction's numerator and denominator.\newlineThe (x10)(x - 10) term cancels out from the second fraction's numerator and the first fraction's denominator.\newlineThe (x+8)(x + 8) term cancels out from the first fraction's numerator and the second fraction's denominator.\newlineAfter canceling, we are left with:\newline62(x+4)\frac{6}{2(x + 4)}1x+4\frac{1}{x + 4} Simplify the remaining expression.\newlineFirst, we can simplify 62\frac{6}{2} to 33.\newlineThen, we notice that we have 1x+4\frac{1}{x + 4} twice in the denominator, so we can combine them:\newline3(x+4)2\frac{3}{(x + 4)^2}

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