Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Imagine the unit circle with a circle. The circle has center 
Q(0,0) and 
P(1,0) lies on it. Another point 
S(1//2,y) lies on the unit circle. Which of the following could be a possible measure of angle PQS?
A. 
-709 pi//6
B. -719 pi/6
C. 
-319 pi//3
D. 
-309 pi//3

Imagine the unit circle with a circle. The circle has center Q(0,0) Q(0,0) and P(1,0) P(1,0) lies on it. Another point S(1/2,y) S(1 / 2, y) lies on the unit circle. Which of the following could be a possible measure of angle PQS?\newlineA. 709pi/6 -709 p i / 6 \newlineB. 719-719 pi/66\newlineC. 319pi/3 -319 p i / 3 \newlineD. 309pi/3 -309 p i / 3

Full solution

Q. Imagine the unit circle with a circle. The circle has center Q(0,0) Q(0,0) and P(1,0) P(1,0) lies on it. Another point S(1/2,y) S(1 / 2, y) lies on the unit circle. Which of the following could be a possible measure of angle PQS?\newlineA. 709pi/6 -709 p i / 6 \newlineB. 719-719 pi/66\newlineC. 319pi/3 -319 p i / 3 \newlineD. 309pi/3 -309 p i / 3
  1. Understand the problem: Understand the problem.\newlineWe need to find the measure of angle PQSPQS on the unit circle where point QQ is the center (0,0)(0,0), point PP is on the circle at (1,0)(1,0), and point SS is on the circle at (12,y)(\frac{1}{2}, y). We are given four options for the measure of angle PQSPQS in terms of π\pi.
  2. Identify circle properties: Identify the properties of the unit circle.\newlineOn the unit circle, the angle is measured in radians from the positive xx-axis (point PP) counterclockwise. The full circle is 2π2\pi radians, so any angle can be expressed as a multiple of π\pi.
  3. Analyze given options: Analyze the given options.\newlineWe need to determine which of the given options could represent the angle PQSPQS. Since the angle is measured from the positive xx-axis, negative angles indicate a clockwise direction. We are looking for an angle that would place point SS at (12,y)(\frac{1}{2}, y) on the unit circle.
  4. Convert to positive angles: Convert the options to a positive angle measure.\newlineSince angles on the unit circle can be expressed as coterminal angles (angles that share the same terminal side), we can add multiples of 2π2\pi to the negative angles to find a positive coterminal angle.
  5. Calculate coterminal angles: Calculate the positive coterminal angles for each option.\newlineA. 709π6+2πk-709 \frac{\pi}{6} + 2\pi \cdot k, where kk is an integer.\newlineB. 719π6+2πk-719 \frac{\pi}{6} + 2\pi \cdot k, where kk is an integer.\newlineC. 319π3+2πk-319 \frac{\pi}{3} + 2\pi \cdot k, where kk is an integer.\newlineD. 309π3+2πk-309 \frac{\pi}{3} + 2\pi \cdot k, where kk is an integer.\newlineWe need to find the smallest positive kk for each option that makes the angle positive.
  6. Find smallest positive kk: Find the smallest positive kk for each option.\newlineA. 709π6+12π6k-709 \frac{\pi}{6} + 12\frac{\pi}{6} \cdot k\newlineB. 719π6+12π6k-719 \frac{\pi}{6} + 12\frac{\pi}{6} \cdot k\newlineC. 319π3+6π3k-319 \frac{\pi}{3} + 6\frac{\pi}{3} \cdot k\newlineD. 309π3+6π3k-309 \frac{\pi}{3} + 6\frac{\pi}{3} \cdot k\newlineWe need to find the smallest kk such that the angle is positive and less than 2π2\pi (since the unit circle is 2π2\pi radians).
  7. Calculate smallest positive angle: Calculate the smallest positive kk for each option.\newlineA. For 709π/6-709 \pi/6, kk must be at least 709/12709/12 to make the angle positive.\newlineB. For 719π/6-719 \pi/6, kk must be at least 719/12719/12 to make the angle positive.\newlineC. For 319π/3-319 \pi/3, kk must be at least 319/6319/6 to make the angle positive.\newlineD. For 709π/6-709 \pi/600, kk must be at least 709π/6-709 \pi/622 to make the angle positive.
  8. Match angles with point S: Determine the smallest positive angle for each option.\newlineA. 709π6+70912×12π6=0-709 \frac{\pi}{6} + \frac{709}{12} \times 12\frac{\pi}{6} = 0 (coterminal with 00)\newlineB. 719π6+72012×12π6=π6-719 \frac{\pi}{6} + \frac{720}{12} \times 12\frac{\pi}{6} = \frac{\pi}{6} (coterminal with π6\frac{\pi}{6})\newlineC. 319π3+3206×6π3=π3-319 \frac{\pi}{3} + \frac{320}{6} \times 6\frac{\pi}{3} = \frac{\pi}{3} (coterminal with π3\frac{\pi}{3})\newlineD. 309π3+3106×6π3=π3-309 \frac{\pi}{3} + \frac{310}{6} \times 6\frac{\pi}{3} = \frac{\pi}{3} (coterminal with π3\frac{\pi}{3})
  9. Choose correct option: Match the coterminal angles with the position of point S.\newlineSince point S has coordinates (1/2,y)(1/2, y), it lies in the first or second quadrant. The angle corresponding to this position must be between 00 and π\pi. Options C and D give us an angle of π/3\pi/3, which is in the first quadrant and could correspond to the position of point S.
  10. Choose correct option: Match the coterminal angles with the position of point S.\newlineSince point S has coordinates (12,y)(\frac{1}{2}, y), it lies in the first or second quadrant. The angle corresponding to this position must be between 00 and π\pi. Options C and D give us an angle of π3\frac{\pi}{3}, which is in the first quadrant and could correspond to the position of point S.Choose the correct option.\newlineOptions C and D are both coterminal with π3\frac{\pi}{3}, which is a possible measure for angle PQS with point S at (12,y)(\frac{1}{2}, y) on the unit circle. Therefore, both C and D could be correct.

More problems from Find Coordinate on Unit Circle