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If the equation y=x2+9y = x^{2} + 9 is graphed in the xyxy-plane, what are the coordinates of the vertex of the graph?\newlineChoose 11 answer:\newline(A) (3,0)(-3,0)\newline(B) (0,3)(0,3)\newline(C) (0,9)(0,9)\newline(D) (9,0)(9,0)

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Q. If the equation y=x2+9y = x^{2} + 9 is graphed in the xyxy-plane, what are the coordinates of the vertex of the graph?\newlineChoose 11 answer:\newline(A) (3,0)(-3,0)\newline(B) (0,3)(0,3)\newline(C) (0,9)(0,9)\newline(D) (9,0)(9,0)
  1. Identify Form: Identify the form of the given quadratic equation.\newlineThe given equation is y=x2+9y = x^2 + 9, which is already in the form y=a(xh)2+ky = a(x - h)^2 + k, where a=1a = 1, h=0h = 0, and k=9k = 9.
  2. Determine Vertex: Determine the vertex of the parabola.\newlineFor a parabola in the form y=a(xh)2+ky = a(x - h)^2 + k, the vertex is at the point (h,k)(h, k). From the equation y=x2+9y = x^2 + 9, we can see that h=0h = 0 and k=9k = 9.
  3. Write Coordinates: Write down the coordinates of the vertex.\newlineThe coordinates of the vertex are (0,9)(0, 9).

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