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If f(x)=(sqrtx+4)/(5), what is the value of f(9), to the nearest hundredth (if necessary)? Answer:

If f(x)=x+45 f(x)=\frac{\sqrt{x}+4}{5} , what is the value of f(9) f(9) , to the nearest hundredth (if necessary)?\newlineAnswer:

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Full solution

Q. If f(x)=x+45 f(x)=\frac{\sqrt{x}+4}{5} , what is the value of f(9) f(9) , to the nearest hundredth (if necessary)?\newlineAnswer:
  1. Substitute xx with 99: To find the value of f(9)f(9), we need to substitute xx with 99 in the function f(x)=(x+4)/5f(x) = (\sqrt{x} + 4) / 5.
  2. Calculate square root of 99: Substitute xx with 99: f(9)=(9+4)/5f(9) = (\sqrt{9} + 4) / 5.
  3. Add 44 to square root: Calculate the square root of 99: 9=3\sqrt{9} = 3.
  4. Divide sum by 55: Add 44 to the square root of 99: 3+4=73 + 4 = 7.
  5. Final result: Divide the sum by 55: 7/5=1.47 / 5 = 1.4.
  6. Final result: Divide the sum by 55: 7/5=1.47 / 5 = 1.4.Since the result is already rounded to the nearest hundredth, there is no need for further rounding.

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