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If
f(x)=(-8)/(9x^(3)), what is the value of
f(2), to the nearest ten-thousandth (if necessary)?
Answer:

If $f(x)=\frac{-8}{9 x^{3}}$ , what is the value of $f(2)$ , to the nearest ten-thousandth (if necessary)? $\newline$ Answer:

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Find trigonometric functions using a calculator

Full solution

Q. If

f(x)=\frac{-8}{9 x^{3}}

, what is the value of

f(2)

, to the nearest ten-thousandth (if necessary)?

\newline

Answer:

Substitute $x$ with $2$ : Substitute the value of $x$ with $2$ in the function $f(x)$ . $f(2) = \frac{-8}{9 \cdot (2)^3}$
Calculate $2^3$ : Calculate the value of $2$ raised to the power of $3$ . $\newline$ $2^3 = 2 \times 2 \times 2 = 8$
Substitute $2^3$ : Substitute the value of $2^3$ into the function. $\newline$ $f(2) = \frac{-8}{9\times 8}$
Perform division: Perform the division to find the value of $f(2)$ . $f(2) = \frac{-8}{72}$ $f(2) = -\frac{1}{9}$
Convert fraction to decimal: Convert the fraction to a decimal rounded to the nearest ten-thousandth. $\newline$ $-\frac{1}{9} \approx -0.1111$

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