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If f(x)=(-7x)/(x^(2)-13), what is the value of f(10), to the nearest hundredth (if necessary)? Answer:

If f(x)=−7xx2−13 f(x)=\frac{-7 x}{x^{2}-13} , what is the value of f(10) f(10) , to the nearest hundredth (if necessary)?\newlineAnswer:

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Full solution

Q. If f(x)=−7xx2−13 f(x)=\frac{-7 x}{x^{2}-13} , what is the value of f(10) f(10) , to the nearest hundredth (if necessary)?\newlineAnswer:
  1. Substitute xx with 1010: To find the value of f(10)f(10), we need to substitute xx with 1010 in the function f(x)=−7xx2−13f(x) = \frac{-7x}{x^2 - 13}.
  2. Perform multiplication and subtraction: Substitute xx with 1010 in the function: f(10)=−7×10102−13f(10) = \frac{-7 \times 10}{10^2 - 13}.
  3. Calculate value in denominator: Perform the multiplication and subtraction in the numerator and denominator: f(10)=−70100−13f(10) = \frac{-70}{100 - 13}.
  4. Divide numerator by denominator: Calculate the value in the denominator: 100−13=87100 - 13 = 87.
  5. Perform division for decimal value: Now, divide the numerator by the denominator: f(10)=−7087f(10) = \frac{-70}{87}.
  6. Round result to nearest hundredth: Perform the division to get the decimal value: f(10)≈−0.8045977011f(10) \approx -0.8045977011.
  7. Round result to nearest hundredth: Perform the division to get the decimal value: f(10)≈−0.8045977011f(10) \approx -0.8045977011.Round the result to the nearest hundredth: f(10)≈−0.80f(10) \approx -0.80.

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