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If
f(x)=7^(x^(2)-3)+13, what is the value of
f(1), to the nearest hundredth (if necessary)?
Answer:

If $f(x)=7^{x^{2}-3}+13$ , what is the value of $f(1)$ , to the nearest hundredth (if necessary)? $\newline$ Answer:

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Find trigonometric functions using a calculator

Full solution

Q. If

f(x)=7^{x^{2}-3}+13

, what is the value of

f(1)

, to the nearest hundredth (if necessary)?

\newline

Answer:

Substitute $x$ with $1$ : To find the value of $f(1)$ , we need to substitute $x$ with $1$ in the function $f(x)=7^{(x^{2}-3)}+13$ .
Calculate the exponent: Substitute $x$ with $1$ : $f(1)=7^{(1^{2})-3}+13$ .
Calculate $7^{-2}$ : Calculate the exponent: $1^{2}-3 = 1-3 = -2$ .
Convert to decimal: Now we have $f(1)=7^{-2}+13$ .
Add to $13$ : Calculate $7^{-2}$ : $7^{-2} = 1/(7^{2}) = 1/49$ .
Round to nearest hundredth: Now we have $f(1)=\frac{1}{49}+13$ .
Round to nearest hundredth: Now we have $f(1)=\frac{1}{49}+13$ .Convert $\frac{1}{49}$ to a decimal: $\frac{1}{49} \approx 0.02040816$ .
Round to nearest hundredth: Now we have $f(1)=\frac{1}{49}+13$ .Convert $\frac{1}{49}$ to a decimal: $\frac{1}{49} \approx 0.02040816$ .Add the decimal to $13$ : $0.02040816 + 13 \approx 13.02040816$ .
Round to nearest hundredth: Now we have $f(1)=\frac{1}{49}+13$ .Convert $\frac{1}{49}$ to a decimal: $\frac{1}{49} \approx 0.02040816$ .Add the decimal to $13$ : $0.02040816 + 13 \approx 13.02040816$ .Round to the nearest hundredth: $13.02040816 \approx 13.02$ .

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