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If
f(x)=3^(x^(2)-9)+11, what is the value of
f(-3), to the nearest thousandth (if necessary)?
Answer:

If $f(x)=3^{x^{2}-9}+11$ , what is the value of $f(-3)$ , to the nearest thousandth (if necessary)? $\newline$ Answer:

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Find trigonometric functions using a calculator

Full solution

Q. If

f(x)=3^{x^{2}-9}+11

, what is the value of

f(-3)

, to the nearest thousandth (if necessary)?

\newline

Answer:

Substitute $x$ with $-3$ : To find the value of $f(-3)$ , we need to substitute $x$ with $-3$ in the function $f(x) = 3^{(x^2-9)}+11$ .
Calculate exponent for $x = -3$ : First, calculate the exponent part of the function for $x = -3$ : $(-3)^2 - 9$ . $\newline$ $(-3)^2 = 9$ , so we have $9 - 9 = 0$ .
Raise $3$ to power of $0$ : Now, we raise $3$ to the power of $0$ , which is $3^0$ . Since any number raised to the power of $0$ is $1$ , we have $3^0 = 1$ .
Add $11$ to result: Next, we add $11$ to the result of $3^0$ , which is $1$ . So, $1 + 11 = 12$ .
Find value of $f(-3)$ : The value of $f(-3)$ is therefore $12$ . Since $12$ is an integer, there is no need to round it to the nearest thousandth.

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