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If f(x)=3^(6x)+9, what is the value of f(1), to the nearest hundredth (if necessary)? Answer:

If f(x)=36x+9 f(x)=3^{6 x}+9 , what is the value of f(1) f(1) , to the nearest hundredth (if necessary)?\newlineAnswer:

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Full solution

Q. If f(x)=36x+9 f(x)=3^{6 x}+9 , what is the value of f(1) f(1) , to the nearest hundredth (if necessary)?\newlineAnswer:
  1. Substitute xx with 11: To find the value of f(1)f(1), we need to substitute xx with 11 in the function f(x)=3(6x)+9f(x) = 3^{(6x)} + 9.
  2. Calculate f(1)f(1): Substituting xx with 11 gives us f(1)=36⋅1+9=36+9f(1) = 3^{6\cdot1} + 9 = 3^6 + 9.
  3. Find f(1)f(1): Calculating 363^6 gives us 729729. So, f(1)=729+9f(1) = 729 + 9.
  4. Add 99 to 729729: Adding 99 to 729729 gives us f(1)=738f(1) = 738.
  5. Check for integer value: Since 738738 is an integer, we do not need to round it to the nearest hundredth. The value of f(1)f(1) is already an integer.

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