If f(x)=(2x-5)(x+2)(x+6)+8, what is the value of f(-6)? Choose 1 answer: (A) -60 (B) 0 (C) 2 (D) 8

Substitute x in f(x): To find the value of f(-6), we need to substitute x with -6 in the function f(x)=(2x-5)(x+2)(x+6)+8.First term substitution: Substitute x with -6 in the first term (2x-5): (2*(-6)-5) = -12 - 5 = -17.Second term substitution: Substitute x with -6 in the second term (x+2): (-6+2) = -4.Third term substitution: Substitute x with -6 in the third term (x+6): (-6+6) = 0.Multiply the terms: Now multiply the results of the three terms together: (-17) * (-4) * (0) = 0, because any number multiplied by zero is zero.Add constant term: Finally, add the constant term 8 to the product of the three terms: 0 + 8 = 8.

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If
f(x)=(2x-5)(x+2)(x+6)+8, what is the value of
f(-6)?
Choose 1 answer:
(A) -60
(B) 0
(C) 2
(D) 8

If $f(x)=(2 x-5)(x+2)(x+6)+8$ , what is the value of $f(-6) ?$ $\newline$ Choose $1$ answer: $\newline$ (A) $-60$ $\newline$ (B) $0$ $\newline$ (C) $2$ $\newline$ (D) $8$

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Q. If

f(x)=(2 x-5)(x+2)(x+6)+8

, what is the value of

f(-6) ?

\newline

Choose

1

answer:

\newline

(A)

-60

\newline

(B)

0

\newline

(C)

2

\newline

(D)

8

Substitute $x$ in $f(x)$ : To find the value of $f(-6)$ , we need to substitute $x$ with $-6$ in the function $f(x)=(2x-5)(x+2)(x+6)+8$ .
First term substitution: Substitute $x$ with $-6$ in the first term $(2x-5)$ : $(2*(-6)-5) = -12 - 5 = -17.$
Second term substitution: Substitute $x$ with $-6$ in the second term $(x+2)$ : $(-6+2) = -4.$
Third term substitution: Substitute $x$ with $-6$ in the third term $(x+6)$ : $\ (-6+6) = 0$ .
Multiply the terms: Now multiply the results of the three terms together: $(-17) \times (-4) \times (0) = 0$ , because any number multiplied by zero is zero.
Add constant term: Finally, add the constant term $8$ to the product of the three terms: $\newline$ $0 + 8 = 8$ .