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If
f(x)=2^(x^(2)+9)-12, what is the value of
f(1), to the nearest tenth (if necessary)?
Answer:

If $f(x)=2^{x^{2}+9}-12$ , what is the value of $f(1)$ , to the nearest tenth (if necessary)? $\newline$ Answer:

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Find trigonometric functions using a calculator

Full solution

Q. If

f(x)=2^{x^{2}+9}-12

, what is the value of

f(1)

, to the nearest tenth (if necessary)?

\newline

Answer:

Substitute $x$ with $1$ : To find the value of $f(1)$ , we need to substitute $x$ with $1$ in the function $f(x)=2^{(x^{2}+9)}-12$ .
Calculate the exponent: Substitute $x$ with $1$ : $f(1)=2^{1^{2}+9}-12$ .
Calculate $2^{10}$ : Calculate the exponent: $1^{(2)}+9 = 1+9 = 10$ .
Subtract $12$ : Now, calculate $2$ raised to the power of $10$ : $2^{10} = 1024$ .
Final value: Subtract $12$ from $1024$ to get the final value: $1024 - 12 = 1012$ .
No rounding necessary: Since the problem asks for the answer to the nearest tenth, we see that $1012$ is already an integer, so no rounding is necessary.

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