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If f(x)=2^(2x)-7, what is the value of f(3), to the nearest hundredth (if necessary)? Answer:

If f(x)=22x−7 f(x)=2^{2 x}-7 , what is the value of f(3) f(3) , to the nearest hundredth (if necessary)?\newlineAnswer:

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Full solution

Q. If f(x)=22x−7 f(x)=2^{2 x}-7 , what is the value of f(3) f(3) , to the nearest hundredth (if necessary)?\newlineAnswer:
  1. Substitute xx with 33: To find the value of f(3)f(3), we need to substitute xx with 33 in the function f(x)=2(2x)−7f(x) = 2^{(2x)} - 7.
  2. Calculate exponent part: Now, calculate the exponent part: 2(2×3)=262^{(2\times3)} = 2^6.
  3. Find f(3)f(3): 262^6 equals 6464, so we have f(3)=64−7f(3) = 64 - 7.
  4. Subtract to get final value: Subtract 77 from 6464 to get the final value of f(3)f(3): 64−7=5764 - 7 = 57.

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