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If
f(x)=(19-x^(2))/(8x), what is the value of
f(-6), to the nearest ten-thousandth (if necessary)?
Answer:

If $f(x)=\frac{19-x^{2}}{8 x}$ , what is the value of $f(-6)$ , to the nearest ten-thousandth (if necessary)? $\newline$ Answer:

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Find trigonometric functions using a calculator

Full solution

Q. If

f(x)=\frac{19-x^{2}}{8 x}

, what is the value of

f(-6)

, to the nearest ten-thousandth (if necessary)?

\newline

Answer:

Substitute $x$ with $-6$ : Substitute $x$ with $-6$ in the function $f(x)$ . $f(-6) = \frac{19 - (-6)^2}{8 \cdot -6}$
Calculate square of $-6$ : Calculate the square of $-6$ . $(-6)^2 = 36$
Substitute square into function: Substitute the square of $-6$ into the function. $\newline$ $f(-6) = \frac{19 - 36}{8 \times -6}$
Perform subtraction in numerator: Perform the subtraction in the numerator. $19 - 36 = -17$
Multiply $8$ by $-6$ : Multiply $8$ by $-6$ in the denominator. $\newline$ $8 \times -6 = -48$
Divide numerator by denominator: Divide the numerator by the denominator to find $f(-6)$ . $f(-6) = \frac{-17}{-48}$
Simplify fraction and round: Simplify the fraction and round to the nearest ten-thousandth if necessary. $\newline$ $f(-6) \approx 0.3542$

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