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If
f(x)=(-18-x^(2))/(4x), what is the value of
f(-6), to the nearest thousandth (if necessary)?
Answer:

If $f(x)=\frac{-18-x^{2}}{4 x}$ , what is the value of $f(-6)$ , to the nearest thousandth (if necessary)? $\newline$ Answer:

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Find trigonometric functions using a calculator

Full solution

Q. If

f(x)=\frac{-18-x^{2}}{4 x}

, what is the value of

f(-6)

, to the nearest thousandth (if necessary)?

\newline

Answer:

Substitute $x$ with $-6$ : Substitute $x$ with $-6$ in the function $f(x)$ . $f(-6) = \frac{-18 - (-6)^2}{4 \cdot -6}$
Calculate square of $-6$ : Calculate the square of $-6$ . $(-6)^2 = 36$
Substitute square into function: Substitute the calculated square into the function. $\newline$ $f(-6) = \frac{-18 - 36}{4 \times -6}$
Perform subtraction in numerator: Perform the subtraction in the numerator. $-18 - 36 = -54$
Multiply $4$ by $-6$ : Multiply $4$ by $-6$ in the denominator. $\newline$ $4 \times -6 = -24$
Divide numerator by denominator: Divide the numerator by the denominator. $f(-6) = \frac{-54}{-24}$
Simplify the fraction: Simplify the fraction. $f(-6) = \frac{54}{24}$
Reduce fraction or convert to decimal: Reduce the fraction to its simplest form or convert it to a decimal. $\newline$ $f(-6) = 2.25$

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