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If f(1)=8 and f(n)=nf(n-1)+1 then find the value of f(3). Answer:

If f(1)=8 f(1)=8 and f(n)=nf(n−1)+1 f(n)=n f(n-1)+1 then find the value of f(3) f(3) .\newlineAnswer:

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Q. If f(1)=8 f(1)=8 and f(n)=nf(n−1)+1 f(n)=n f(n-1)+1 then find the value of f(3) f(3) .\newlineAnswer:
  1. Calculate f(2)f(2): We are given that f(1)=8f(1) = 8. To find f(3)f(3), we need to find f(2)f(2) first, using the recursive formula f(n)=nf(n−1)+1f(n) = nf(n-1) + 1.\newlineLet's calculate f(2)f(2) using f(1)f(1).\newlinef(2)=2f(1)+1f(2) = 2f(1) + 1\newlinef(2)=2(8)+1f(2) = 2(8) + 1\newlinef(2)=16+1f(2) = 16 + 1\newlinef(1)=8f(1) = 800
  2. Find f(3)f(3): Now that we have f(2)f(2), we can use it to find f(3)f(3) using the same recursive formula.\newlinef(3)=3f(2)+1f(3) = 3f(2) + 1\newlinef(3)=3(17)+1f(3) = 3(17) + 1\newlinef(3)=51+1f(3) = 51 + 1\newlinef(3)=52f(3) = 52

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