If f(1)=8 and f(n)=-3f(n-1)+1 then find the value of f(5). Answer:

Given Information: We are given that f(1) = 8. To find f(5), we need to find the values of f(2), f(3), f(4), and then f(5) using the recursive formula f(n) = -3f(n-1) + 1. Let's start by finding f(2). f(2) = -3f(2-1) + 1 f(2) = -3f(1) + 1 f(2) = -3(8) + 1 f(2) = -24 + 1 f(2) = -23Find f(2): Now, let's find f(3) using the value of f(2). f(3) = -3f(3-1) + 1 f(3) = -3f(2) + 1 f(3) = -3(-23) + 1 f(3) = 69 + 1 f(3) = 70Find f(3): Next, we calculate f(4) using the value of f(3). f(4) = -3f(4-1) + 1 f(4) = -3f(3) + 1 f(4) = -3(70) + 1 f(4) = -210 + 1 f(4) = -209Calculate f(4): Finally, we find f(5) using the value of f(4). f(5) = -3f(5-1) + 1 f(5) = -3f(4) + 1 f(5) = -3(-209) + 1 f(5) = 627 + 1 f(5) = 628

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If
f(1)=8 and
f(n)=-3f(n-1)+1 then find the value of
f(5).
Answer:

If $f(1)=8$ and $f(n)=-3 f(n-1)+1$ then find the value of $f(5)$ . $\newline$ Answer:

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Q. If

f(1)=8

and

f(n)=-3 f(n-1)+1

then find the value of

f(5)

\newline

Answer:

Given Information: We are given that $f(1) = 8$ . To find $f(5)$ , we need to find the values of $f(2)$ , $f(3)$ , $f(4)$ , and then $f(5)$ using the recursive formula $f(n) = -3f(n-1) + 1$ . $\newline$ Let's start by finding $f(2)$ . $\newline$ $f(2) = -3f(2-1) + 1$ $\newline$ $f(2) = -3f(1) + 1$ $\newline$ $f(5)$ $0$ $\newline$ $f(5)$ $1$ $\newline$ $f(5)$ $2$
Find $f(2)$ : Now, let's find $f(3)$ using the value of $f(2)$ .
$f(3) = -3f(3-1) + 1$
$f(3) = -3f(2) + 1$
$f(3) = -3(-23) + 1$
$f(3) = 69 + 1$
$f(3) = 70$
Find $f(3)$ : Next, we calculate $f(4)$ using the value of $f(3)$ .
$f(4) = -3f(4-1) + 1$
$f(4) = -3f(3) + 1$
$f(4) = -3(70) + 1$
$f(4) = -210 + 1$
$f(4) = -209$
Calculate $f(4)$ : Finally, we find $f(5)$ using the value of $f(4)$ .
$f(5) = -3f(5-1) + 1$
$f(5) = -3f(4) + 1$
$f(5) = -3(-209) + 1$
$f(5) = 627 + 1$
$f(5) = 628$