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If 
f(1)=4 and 
f(n)=nf(n-1)-2 then find the value of 
f(5).
Answer:

If f(1)=4 f(1)=4 and f(n)=nf(n1)2 f(n)=n f(n-1)-2 then find the value of f(5) f(5) .\newlineAnswer:

Full solution

Q. If f(1)=4 f(1)=4 and f(n)=nf(n1)2 f(n)=n f(n-1)-2 then find the value of f(5) f(5) .\newlineAnswer:
  1. Given Information: We are given that f(1)=4f(1) = 4. To find f(5)f(5), we need to use the recursive formula f(n)=nf(n1)2f(n) = nf(n-1) - 2, starting with n=2n = 2 and working our way up to n=5n = 5.
  2. Calculate f(2)f(2): First, let's find f(2)f(2) using the formula:\newlinef(2)=2f(21)2f(2) = 2f(2-1) - 2\newlinef(2)=2f(1)2f(2) = 2f(1) - 2\newlinef(2)=2(4)2f(2) = 2(4) - 2\newlinef(2)=82f(2) = 8 - 2\newlinef(2)=6f(2) = 6
  3. Calculate f(3)f(3): Next, we find f(3)f(3) using the value of f(2)f(2) we just calculated:\newlinef(3)=3f(31)2f(3) = 3f(3-1) - 2\newlinef(3)=3f(2)2f(3) = 3f(2) - 2\newlinef(3)=3(6)2f(3) = 3(6) - 2\newlinef(3)=182f(3) = 18 - 2\newlinef(3)=16f(3) = 16
  4. Calculate f(4)f(4): Now, we calculate f(4)f(4) using the value of f(3)f(3):
    f(4)=4f(41)2f(4) = 4f(4-1) - 2
    f(4)=4f(3)2f(4) = 4f(3) - 2
    f(4)=4(16)2f(4) = 4(16) - 2
    f(4)=642f(4) = 64 - 2
    f(4)=62f(4) = 62
  5. Calculate f(5)f(5): Finally, we find f(5)f(5) using the value of f(4)f(4):
    f(5)=5f(51)2f(5) = 5f(5-1) - 2
    f(5)=5f(4)2f(5) = 5f(4) - 2
    f(5)=5(62)2f(5) = 5(62) - 2
    f(5)=3102f(5) = 310 - 2
    f(5)=308f(5) = 308

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