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If f(1)=2 and f(n)=nf(n-1)-4 then find the value of f(3). Answer:

If f(1)=2 f(1)=2 and f(n)=nf(n−1)−4 f(n)=n f(n-1)-4 then find the value of f(3) f(3) .\newlineAnswer:

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Q. If f(1)=2 f(1)=2 and f(n)=nf(n−1)−4 f(n)=n f(n-1)-4 then find the value of f(3) f(3) .\newlineAnswer:
  1. Calculate f(2)f(2): We are given that f(1)=2f(1) = 2. To find f(3)f(3), we need to first find f(2)f(2) using the recursive formula f(n)=nf(n−1)−4f(n) = nf(n-1) - 4.\newlineLet's calculate f(2)f(2):\newlinef(2)=2f(2−1)−4f(2) = 2f(2-1) - 4\newlinef(2)=2f(1)−4f(2) = 2f(1) - 4\newlinef(2)=2(2)−4f(2) = 2(2) - 4\newlinef(2)=4−4f(2) = 4 - 4\newlinef(1)=2f(1) = 200
  2. Calculate f(3)f(3): Now that we have f(2)f(2), we can use it to find f(3)f(3) using the same recursive formula.\newlineLet's calculate f(3)f(3):\newlinef(3)=3f(3−1)−4f(3) = 3f(3-1) - 4\newlinef(3)=3f(2)−4f(3) = 3f(2) - 4\newlinef(3)=3(0)−4f(3) = 3(0) - 4\newlinef(3)=0−4f(3) = 0 - 4\newlinef(3)=−4f(3) = -4

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