If f(1)=1 and f(n)=f(n-1)-1 then find the value of f(5). Answer:

Base Case Given: We are given that f(1) = 1. This is our base case.Recursive Formula: We are also given a recursive formula: f(n) = f(n-1) - 1. This means that to find f(n), we subtract 1 from the value of f at the previous integer, which is f(n-1).Finding f(5): To find f(5), we need to find the values of f(4), f(3), f(2), and we already know f(1).Calculating f(2): Using the recursive formula, f(2) = f(1) - 1. Since f(1) = 1, we have f(2) = 1 - 1 = 0.Calculating f(3): Next, f(3) = f(2) - 1. We found that f(2) = 0, so f(3) = 0 - 1 = -1.Calculating f(4): Then, f(4) = f(3) - 1. We found that f(3) = -1, so f(4) = -1 - 1 = -2.Calculating f(5): Finally, f(5) = f(4) - 1. We found that f(4) = -2, so f(5) = -2 - 1 = -3.

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If
f(1)=1 and
f(n)=f(n-1)-1 then find the value of
f(5).
Answer:

If $f(1)=1$ and $f(n)=f(n-1)-1$ then find the value of $f(5)$ . $\newline$ Answer:

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Q. If

f(1)=1

and

f(n)=f(n-1)-1

then find the value of

f(5)

\newline

Answer:

Base Case Given: We are given that $f(1) = 1$ . This is our base case.
Recursive Formula: We are also given a recursive formula: $f(n) = f(n-1) - 1$ . This means that to find $f(n)$ , we subtract $1$ from the value of $f$ at the previous integer, which is $f(n-1)$ .
Finding $f(5)$ : To find $f(5)$ , we need to find the values of $f(4)$ , $f(3)$ , $f(2)$ , and we already know $f(1)$ .
Calculating $f(2)$ : Using the recursive formula, $f(2) = f(1) - 1$ . Since $f(1) = 1$ , we have $f(2) = 1 - 1 = 0$ .
Calculating $f(3)$ : Next, $f(3) = f(2) - 1$ . We found that $f(2) = 0$ , so $f(3) = 0 - 1 = -1$ .
Calculating $f(4)$ : Then, $f(4) = f(3) - 1$ . We found that $f(3) = -1$ , so $f(4) = -1 - 1 = -2$ .
Calculating $f(5)$ : Finally, $f(5) = f(4) - 1$ . We found that $f(4) = -2$ , so $f(5) = -2 - 1 = -3$ .