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If 
f(1)=1 and 
f(n+1)=-5f(n)-4 then find the value of 
f(5).
Answer:

If f(1)=1 f(1)=1 and f(n+1)=5f(n)4 f(n+1)=-5 f(n)-4 then find the value of f(5) f(5) .\newlineAnswer:

Full solution

Q. If f(1)=1 f(1)=1 and f(n+1)=5f(n)4 f(n+1)=-5 f(n)-4 then find the value of f(5) f(5) .\newlineAnswer:
  1. Given initial condition: We are given the initial condition f(1)=1f(1) = 1 and the recursive formula f(n+1)=5f(n)4f(n+1) = -5f(n) - 4. To find f(5)f(5), we need to find the values of f(2)f(2), f(3)f(3), and f(4)f(4) first, using the recursive formula.
  2. Find f(2)f(2): Using the recursive formula, let's find f(2)f(2):
    f(2)=5f(1)4f(2) = -5f(1) - 4
    f(2)=5(1)4f(2) = -5(1) - 4
    f(2)=54f(2) = -5 - 4
    f(2)=9f(2) = -9
  3. Find f(3)f(3): Now, let's find f(3)f(3):
    f(3)=5f(2)4f(3) = -5f(2) - 4
    f(3)=5(9)4f(3) = -5(-9) - 4
    f(3)=454f(3) = 45 - 4
    f(3)=41f(3) = 41
  4. Find f(4)f(4): Next, we find f(4)f(4):
    f(4)=5f(3)4f(4) = -5f(3) - 4
    f(4)=5(41)4f(4) = -5(41) - 4
    f(4)=2054f(4) = -205 - 4
    f(4)=209f(4) = -209
  5. Find f(5)f(5): Finally, we find f(5)f(5):
    f(5)=5f(4)4f(5) = -5f(4) - 4
    f(5)=5(209)4f(5) = -5(-209) - 4
    f(5)=10454f(5) = 1045 - 4
    f(5)=1041f(5) = 1041

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